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江蘇省高校計(jì)算機(jī)等級(jí)考試命題研究院 江蘇省高校計(jì)算機(jī)等級(jí)考試輔導(dǎo)
2010年3月江蘇VB考試真題

絕密★ 啟用前

2010年春

江蘇省高等學(xué)校非計(jì)算機(jī)專業(yè)學(xué)生

計(jì)算機(jī)基礎(chǔ)知識(shí)和應(yīng)用能力等級(jí)考試

二級(jí)試卷

試卷語(yǔ)種:VB語(yǔ)言

 

說(shuō)  明:

1.本試卷包括計(jì)算機(jī)基礎(chǔ)知識(shí)部分和程序設(shè)計(jì)部分,考試時(shí)間共12 0分鐘;

2.本試卷滿分為60分,分選擇題和填空題,試卷不分AB類型;

3.計(jì)算機(jī)基礎(chǔ)知識(shí)部分全部是選擇題(20),程序設(shè)計(jì)部分分為選擇題(1 0

  )和填空題(30)兩種;

4.選擇題用答題卡答題。每一項(xiàng)有A、BC、D四個(gè)可供選擇的答案,請(qǐng)選

  擇其中一個(gè)你認(rèn)為正確的答案,用HB鉛筆涂寫(xiě)在答題卡的相應(yīng)答題號(hào)內(nèi)。

  每選對(duì)一項(xiàng)得1分,不選或選錯(cuò)不得分;

5.填空題用答題紙答題。請(qǐng)將答案用藍(lán)、黑色鋼筆或圓珠筆填寫(xiě)在答題紙的

  相應(yīng)答題號(hào)內(nèi),每個(gè)答案只占一行,不得換行。每填對(duì)一個(gè)答案得1分,

  不填或填錯(cuò)不得分;

6.請(qǐng)認(rèn)真填寫(xiě)并仔細(xì)核對(duì)答題卡和答題紙上的學(xué)校名稱、準(zhǔn)考證號(hào)和姓名是

  否填寫(xiě)正確。

7.考試結(jié)束時(shí)將試卷、答題卡和答題紙放在桌上,不得帶走。待監(jiān)考人員收

  畢清點(diǎn)后,方可離場(chǎng)。

 

 

 

 

 

 

 

 

 第一部分:(公共基礎(chǔ)知識(shí))

參見(jiàn)2010春VFP考試試題

  

 第二部分Visual Basic程序設(shè)計(jì)  .

一、選擇題(用答題卡答題,答案依次填在2130答題號(hào)內(nèi))

21.關(guān)于窗體,以下敘述中正確的是    21    。

    A.僅當(dāng)窗體上沒(méi)有可以獲得焦點(diǎn)的控件時(shí),窗體才可以獲得焦點(diǎn)

    B.一個(gè)VB工程只能從某個(gè)指定的窗體開(kāi)始啟動(dòng)

    C.只有窗體可以作為控件的容器

    D.Unload MeEnd語(yǔ)句的效果總是等同的

22.a為長(zhǎng)整型變量,則執(zhí)行a=12 : Print Len(a);Len(Str(a)); Len(CStr(a))后,在窗體上看到的是    22   

    A.4 2 3    B.2  3  2    C.4 3  2 D.2  2  3

23.數(shù)學(xué)表達(dá)式 對(duì)應(yīng)的visual Basic表達(dá)式是  23   。

    A.Cos(30*3.14159/180)/(4*y+Ln(x))+Exp(2)

    B.Cos(30*3.14159/180)/(4*y+Log(x))+Exp(2)

    C.Cos(30*3.14159/180)/(4*y+Ln(x))+e^2

    D.Cos(30)/(4*y+Log(x))+e^2

24.表達(dá)式Fix(-2.5)+Int(-3.5)+CInt(-2.5)的值是   24   

    A.-8    B.-7    C.-6    D.-5

25.以下說(shuō)法中,錯(cuò)誤的是   25   

    A.使用缺省Preserve關(guān)鍵字的ReDim語(yǔ)句可以改變數(shù)組的維數(shù)和大小

    B.ReDim語(yǔ)句只能出現(xiàn)在過(guò)程中

    c.使用ReDim語(yǔ)句重新定義的動(dòng)態(tài)數(shù)組,只能比原數(shù)組大

    D.使用ReDim語(yǔ)句可以對(duì)動(dòng)態(tài)數(shù)組的所有元素進(jìn)行初始化

26.下列關(guān)于菜單的說(shuō)法中,錯(cuò)誤的是.    26    。

  A.可以為菜單項(xiàng)選定快捷鍵

  B.若在"標(biāo)題"文本框中鍵入連字符(),則可在菜單的兩個(gè)菜單命令項(xiàng)之間加一條分隔線

  C.除了Click事件之外,菜單項(xiàng)還可以響應(yīng)其他事件

  D.菜單編輯器的"名稱"文本框用于輸入菜單項(xiàng)的名稱

27.以下有關(guān)過(guò)程中形式參數(shù)的描述中,錯(cuò)誤的是  27   。

  A.函數(shù)過(guò)程可以沒(méi)有形式參數(shù)

  B.事件過(guò)程一定沒(méi)有形式參數(shù)

  C.形參數(shù)組只能按地址與實(shí)參數(shù)組結(jié)合

  D.窗體與控件也可以作為過(guò)程的參數(shù)

28.以下表達(dá)式中,可以表示"AB之一大于0"的是  28  。

    A*B<=0  A>0 Xor B>0  A>0 Or B>0  A>0 And B<=0 Or B>0 And A<=0

    A.①③    B.③④    C.②④    D.①②④

29.設(shè)變量A為長(zhǎng)整型,則下面不能正常執(zhí)行的語(yǔ)句是 29    。

    AA=32768*2    BA=2*1.5*16384

    CA=16384*2    DA=190^2

30.以下有關(guān)滾動(dòng)條控件(ScrollBar)的說(shuō)法中錯(cuò)誤的是   30   。

  A.只能在設(shè)計(jì)時(shí)設(shè)置MaxMin屬性值

  BValue屬性返回滾動(dòng)條內(nèi)滑塊當(dāng)前所處位置的值

  C.拖動(dòng)滾動(dòng)條內(nèi)滑塊時(shí),將觸發(fā)滾動(dòng)條的Scroll事件

  D.單擊滾動(dòng)箭頭時(shí),將觸發(fā)滾動(dòng)條的Change事件

:填空題

1.執(zhí)行下面的程序后,A(1,4)的值是_____,A(2,3)的值是_______,A(3,2)的值是

Option Explicit

Option Base 1

Private Sub Command1_Click()

  Dim a(4, 4) As Integer, ub As Integer

  Dim i As Integer, j As Integer, n As Integer

  ub = UBound(a, 1)

  n = 0

  For i = ub To 1 Step -1

    For j = 1 To ub + 1 - i

      n = n + 1

      a(j, j + i - 1) = n

    Next j

  Next i

  For i = ub To 2 Step -1

    For j = ub To i Step -1

       a(j, j - i + 1) = a(5 - j, 4 - j + i)

    Next j

  Next i

  For i = 1 To ub

    For j = 1 To ub

      Picture1.Print a(i, j);

    Next j

    Picture1.Print

  Next i

End Sub

2.InputBox函數(shù)對(duì)話框中輸入4(或直接單擊確定按鈕)窗體顯示的第一行內(nèi)容__(4)___,第二行是__(5)___,第四行是__(6)___

Option Explicit

private Sub command1_Click()

  dim days as integer

  Days=InputBox("輸入正整數(shù)",4)

  print fun(days)

End Sub 

 

private function fun(d as integer) as integer

  if D=1 then

    fun=1

  else

    fun=2*fun(D-1)+1

    print D;fun

  end if

End Function

3窗體顯示的第一行是__(7)_____第三行是__(8)_____最后一行是___(9)__

private sub command1_Click()

  Dim i as integer, k as integer

  For i=1 to 5

    k=fun(i)+I

    print k

  next i

  print i

End Sub

Function Fun(N as integer) as Integer

  Static M as integer

  Dim j as integer

  M=M+N

  N=N+1

  For J=1 To M

    J=J+2

    Fun=Fun+J

  Next J

  Fun=Fun+N

End Function

4.窗體顯示的第一行是__(10)_____第三行是__(11)_____,最后一行是_(12)____

Option Explicit

Private Sub Command1_Click()

  Dim S as String,N as Integer

  S="3AB"

  N=14

  Print Convert(S,N)

End Sub

Private Function Convert(S As string,N as Integer) as Long

  Dim St as string, L as Integer, I as integer

  L=Len(s)

  Do while L>=1

    st=Left(s,1)

   if  st>"9" then

     st=Asc(st)-55

   end if

   Covert=Convert+Val(st)*N^(L-1)

   print Val(st)*N^(L-1)

   L=L-1

   s=Right(S,L)

  Loop

End Function

5.窗體顯示的第一行是__(13)___,第二行是__(14)____,第三行是___(15)__

Option Explicit

Private Sub Command1_Click()

  Dim s as string, k as integer, ch() as string

  Dim P as string,i as integer

  s=Ucase("Meet me after the class.")

  For i=1 to Len(s)

    If Mid(s,i,1)<="Z" and Mid(s,i,1)>="A" then

      p=p & Mid(s,i,1)

    ElseIf p<>"" then

      k=k+1

      Redim Preserve ch(k)

      ch(k)=p

      p=""

    End if

  Next i

  For i=1 to Ubound(ch)

    if len(ch(i))<=2 then

       Call move_c(ch(i),1)

    else

       Call move_c(ch(i),2)

    end if

    print ch(i)

  next i

End SUb

Private Sub Move_c(s as string, k as integer)

   Dim i as integer, j as integer, p as string*1

   For i=1 to k

      p=Right(s,1)

      For j=Len(s)-1 to 1 step -1

         Mid(s,j+1,1)=Mid(s,j,1)

      Next j

      s=p & Right(s,Len(s)-1)

   next i

End Sub

6.下面的程序是求的近似值,當(dāng)?shù)?/SPAN>n項(xiàng)的絕對(duì)值小于10^-5時(shí)終止計(jì)算

=1-1/3+1/5-1/7+…(-1)

option explicit

Private Sub Command1_Click()

  dim n as long, s as single, t as single, pi as single

  Const eps=0.00001

  n=1

  t=1

  s=0

  do

    s=s+t

    n=n+1

    t=___(16)______

  Loop Until __(17)______

  pi=s*4

  Label1.Caption ="的近似值為:"

End Sub

7.下面程序的功能是,找出滿足以下條件的三位整數(shù),不含數(shù)字0,

且任意交換數(shù)字位置所得到的數(shù),均能被6整除

Option explicit

Private sub Command1_Click()

  dim i as integer, j as integer, k as integer, st as string

  Dim a(6) as integer

  For i=100 to 999

    if ______(18)_________ then

      For j=1 to 6

        if a(j) Mod 6<>0 then Exit For

      Next j

      if______(19)________THen

        st=st & str(i)

        k=k+1

        if k mod 3 =0 then st=st & vbcrlf

      End if

    End if

  Next I

  Text1=st

End Sub

Private Function fj(a() as integer, s as string) as Boolean

  Dim n as Integer, i as integer, j as integer

  if Instr(s,"0")<>0 then

    ___(20)___

  end if

  For i=1 to 3

    For j=1 to 2

      n=n+1

      ____(21)___

      s=Left(s,1) & Right(s,1) & Mid(s,2,1)

    Next j

    s=Right(s,1) & left(s,2)

  Next i

  fj=True

End Function

 

8.下面程序的功能是求兩個(gè)特大整數(shù)之和,由于vb中能夠表示的整數(shù)大小有一定限制,所以必須用新的方法求特大整數(shù)之和,本程序?qū)⑻卮笳麛?shù)使用字符類型進(jìn)行處理,其中函數(shù)add用于求兩個(gè)1位整數(shù)之和,參數(shù)c用于保存進(jìn)位,注意,求和前需首先將兩個(gè)整數(shù)按位對(duì)齊

 

option explicit

private Sub command1_Click()

   Dim s1 as string, s2 as string, s3 as string

   dim i as integer, n1 as integer, n2 as integer

   dim c as integer, n as integer

   s1=text1 : s2=Text2

   n=______22_____

   if sgn(n)>0 then

     s2=________23__________

   elseif Sgn(N)<0 then

     s1=String(Abs(n),"0") & s1

   end if

   For i=len(s1) to 1 step -1

     n1=Val(Mid(s1,i,1))

     n2=Val(Mid(s2,i,1))

     s3=_______(24)________

   Next i

   if c<>0 then s3=________(25)________

   Text3=s3

End Sub

Private Function Add(x as integer, y as integer, c as Integer) as string

  Add=Cstr((x+y+c) Mod 10)

  _________(26)________

End Function

9.

Option Explicit

Private Sub Command1_Click()

  dim i as long,i2 as long, flag as Boolean

  Dim a(0 to 9) as integer, b(0 to 9) as integer

  For i=100000 to 160000

     Call Validate(i,a,flag)

     if flag then

       i2=i*6

       call Validate(i2,b,flag)

       if flag and Compare(a,b) then

         List1.AddItem i & "  " & i2

       End if

     End if

  Next i

end sub

Private Sub validate(n as long, a() as Integer, f as Boolean)

    dim p as integer, i as integer

    Erase a

    f=false

    for i=1 to len(cstr(N))

         p=___(27)___

      if a(p)=1 then

        exit sub

      else

       a(p)=1

      end if

    next i

    ___(29) f=true

End Sub

 

Private Function Compare(a() as integer, b() as integer) as Boolean

  dim j as integer

  compare=false

  for j=1 to Ubound(a)

    if a(j)<>b(j) then

      ____(30)____exit function

    End if

  next j

  Compare=true

End Function